C 语言指针作为函数返回值

#include <stdio.h>
#include <string.h>

char *strlong(char *str1, char *str2){
    if(strlen(str1) >= strlen(str2)){
        return str1;
    }else{
        return str2;
    }
}

int main(){
    char str1[30], str2[30], *str;
    gets(str1);
    gets(str2);
    str = strlong(str1, str2);
    printf("Longer string: %s\n", str);

    return 0;
}

C Language↲
	c.biancheng.net↲
	Longer string: c.biancheng.net

#include <stdio.h>

int *func(){
    int n = 100;
    return &n;
}

int main(){
    int *p = func(), n;
    n = *p;
    printf("value = %d\n", n);
    return 0;
}

value = 100

#include <stdio.h>

int *func(){
    int n = 100;
    return &n;
}

int main(){
    int *p = func(), n;
    printf("c.biancheng.net\n");
    n = *p;
    printf("value = %d\n", n);
    return 0;
}

c.biancheng.net
	value = -2

意见反馈